Question:medium

Find the odd one out: 8, 27, 64, 100, 125.

Show Hint

Four of these are perfect cubes.
Updated On: Jul 8, 2026
  • 27
  • 64
  • 100
  • 125
Show Solution

The Correct Option is C

Solution and Explanation

List cube roots: $\sqrt[3]{8}=2$, $\sqrt[3]{27}=3$, $\sqrt[3]{64}=4$, $\sqrt[3]{125}=5$, but $\sqrt[3]{100}$ is not a whole number. Hence 100 is the exception.
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