To find the mean deviation about the mean for the given data set, we need to follow these steps:
Let's break down the computations:
Given values:
| X | f |
|---|---|
| 2 | 7 |
| 4 | 4 |
| 6 | 5 |
| 8 | 4 |
| 10 | 5 |
The mean (\(\bar{X}\)) is calculated as:
\(\bar{X} = \frac{\sum (X \cdot f)}{\sum f}\)
Calculate \(\sum (X \cdot f)\):
\((2 \times 7) + (4 \times 4) + (6 \times 5) + (8 \times 4) + (10 \times 5) = 14 + 16 + 30 + 32 + 50 = 142\)
Calculate \(\sum f\):
\(7 + 4 + 5 + 4 + 5 = 25\)
So, the mean is:
\(\bar{X} = \frac{142}{25} = 5.68\)
Calculate the absolute deviations from the mean:
| X | |X - \(\bar{X}\)| |
|---|---|
| 2 | |2 - 5.68| = 3.68 |
| 4 | |4 - 5.68| = 1.68 |
| 6 | |6 - 5.68| = 0.32 |
| 8 | |8 - 5.68| = 2.32 |
| 10 | |10 - 5.68| = 4.32 |
| X | |X - \(\bar{X}\)| | f | f × |X - \(\bar{X}\)| |
|---|---|---|---|
| 2 | 3.68 | 7 | 3.68 × 7 = 25.76 |
| 4 | 1.68 | 4 | 1.68 × 4 = 6.72 |
| 6 | 0.32 | 5 | 0.32 × 5 = 1.60 |
| 8 | 2.32 | 4 | 2.32 × 4 = 9.28 |
| 10 | 4.32 | 5 | 4.32 × 5 = 21.60 |
Sum of all products \(= 25.76 + 6.72 + 1.60 + 9.28 + 21.60 = 64.96\)
Mean deviation about the mean is given by:
\(\frac{\text{Sum of (f × |X - \(\bar{X}\)|)}}{\sum f} = \frac{64.96}{25} = 2.5984\)
Rounding off to one decimal place, the mean deviation is approximately 2.5.
Thus, the mean deviation about the mean for the given data is 2.5.