Question:medium

Find the energy of each of the photons which (i) corresponds to light of frequency 3×1015 Hz. (ii) have a wavelength of 0.50 Å

Updated On: Jan 21, 2026
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Solution and Explanation

Given:

Planck’s constant, h = 6.626 × 10−34 J s
Speed of light, c = 3.0 × 108 m s−1


(i) Photon corresponding to frequency 3 × 1015 Hz

Energy of photon:

E = hν

E = (6.626 × 10−34) × (3 × 1015)

E = 1.99 × 10−18 J


(ii) Photon having wavelength 0.50 Å

Wavelength, λ = 0.50 Å = 0.50 × 10−10 m

Energy of photon:

E = hc / λ

E = (6.626 × 10−34 × 3.0 × 108) / (0.50 × 10−10)

E = 3.98 × 10−15 J


Final Answers:

(i) Energy of photon = 1.99 × 10−18 J
(ii) Energy of photon = 3.98 × 10−15 J

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