Question

Study the circuit shown in which two resistors X and Y of resistances 3 Ω and 6 Ωrespectively are joined in series with a battery of 2V.

Find the current drawn from the battery by the series combination of the two resistors (X and Y). 

Hint:

In a series circuit, the current remains the same throughout, but in a parallel circuit, the potential difference across each component is identical.

Answer 1

For a series circuit, the total resistance \(R_{{total}}\) equals the sum of individual resistances: \[ R_{{total}} = R_X + R_Y = 3 \, \Omega + 6 \, \Omega = 9 \, \Omega \] Applying Ohm's law \(I = \frac{V}{R}\) with \(V = 2V\) and \(R_{{total}} = 9 \, \Omega\), the current \(I\) is: \[ I = \frac{2V}{9 \, \Omega} = 0.222 \, {A} \] Therefore, the current from the battery is \(0.222 \, {A}\).