Question:medium

Find out the major product formed from the following reaction.\([ \text{Me: } -\text{CH}_3 ]\)

Updated On: Jan 13, 2026
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The Correct Option is B

Solution and Explanation

Explanation 62
Step 1: \( S_N2 \) reaction with dimethylamine (\( \text{Me}_2\text{NH} \)) replaces a bromine atom with \( \text{Me}_2\text{N} \), creating an intermediate with a quaternary amine on an adjacent carbon.
Step 2: Deprotonation of the intermediate yields an alkene.
Step 3: A second \( S_N2 \) reaction with dimethylamine substitutes the remaining bromine atom with another \( \text{Me}_2\text{N} \) group.
The final product features two \( \text{Me}_2\text{N} \) groups at adjacent positions on the cyclopentane ring.
This mechanism applies to both cis and trans isomers, resulting in identical products.

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