





Step 1: \( S_N2 \) reaction with dimethylamine (\( \text{Me}_2\text{NH} \)) replaces a bromine atom with \( \text{Me}_2\text{N} \), creating an intermediate with a quaternary amine on an adjacent carbon.
Step 2: Deprotonation of the intermediate yields an alkene.
Step 3: A second \( S_N2 \) reaction with dimethylamine substitutes the remaining bromine atom with another \( \text{Me}_2\text{N} \) group.
The final product features two \( \text{Me}_2\text{N} \) groups at adjacent positions on the cyclopentane ring.
This mechanism applies to both cis and trans isomers, resulting in identical products.
Draw the structure of the major monohalo product for each of the following reactions: 
Propene to 1-Iodopropane
Br\(_2\)/CS\(_2\)
