Question

Find : \( \int \tan^{-1}\left(\frac{1 - x}{1 + x}\right) \, dx \)

Hint:

Alternatively, substituting \( x = \tan\theta \) directly simplifies the inner fraction to \( \tan(\frac{\pi}{4} - \theta) \), transforming the entire inverse function expression into a simple linear expression \( \frac{\pi}{4} - \theta \) right from the start.

Answer 1