Question

Figure shows a rectangular frame situated in a constant magnetic field. A wire BC of length \(1\text{ m}\) is moved out with velocity \(4\text{ m/s}\). Magnetic field strength is \(0.15\text{ T}\). Force acting on the wire \(BC\) is

• A. \(18\text{ N}\)
• B. \(1.8\text{ N}\)
• C. \(0.18\text{ N}\)
• D. \(0.018\text{ N}\)

Hint:

Moving conductor shortcut: $F = \frac{B^2 \ell^2 v}{R}$

Answer 1

The Correct Option is D