Figure 9.21 (a) shows a thin liquid film supporting a small weight = 4.5 × 10-2 N. What is the weight supported by a film of the same liquid at the same temperature in Fig. (b) and (c) ? Explain your answer physically.
A liquid film has two free surfaces, so the total length along which surface tension acts is \(2l\).
For case (a): Surface tension \( T = \dfrac{W_a}{2l} = \dfrac{4.5 \times 10^{-2}}{2 \times 0.4} = 5.625 \times 10^{-2}\,\text{N m}^{-1} \)
The liquid and temperature are the same in (a), (b), and (c), so the surface tension \(T\) is the same in all three cases.
In (b) and (c), the length of the film that supports the weight is again \( l = 0.4\,\text{m} \), and the film still has two free surfaces. Hence, the supporting force is again \( F = 2Tl \), which is unchanged from case (a).
Therefore, the weight supported in (b) and in (c) is the same as in (a): \( W_b = W_c = 4.5 \times 10^{-2}\,\text{N} \).
Consider a water tank shown in the figure. It has one wall at \(x = L\) and can be taken to be very wide in the z direction. When filled with a liquid of surface tension \(S\) and density \( \rho \), the liquid surface makes angle \( \theta_0 \) (\( \theta_0 < < 1 \)) with the x-axis at \(x = L\). If \(y(x)\) is the height of the surface then the equation for \(y(x)\) is: (take \(g\) as the acceleration due to gravity) 