The given reaction sequence involves the transformation of a compound through different stages to arrive at the final product 'C'. Let's analyze each step:
Fig,
The starting compound is a benzene ring with an \(\text{-OH}\) (phenolic) and \(\text{-CHO}\) (aldehyde) substituent.
The first step involves bromination using \(\text{Br}_2\). Bromination typically occurs at the para-position relative to -OH, which is an activating, ortho-para directing group. Product 'A' is likely a brominated phenol-aldehyde compound.
Next, \(\text{NH}_2\text{OH}\) (hydroxylamine) reacts with the aldehyde group to form an oxime. This reaction is specific to carbonyl compounds, converting the aldhehyde group into a \(\text{C=N-OH}\) group, resulting in product 'B'.
Finally, \(\text{P}_2\text{O}_5\) is used. This is a strong dehydrating agent, indicating that the oxime undergoes dehydration to form a nitrile. Hence, from an oxime, the conversion leads to product 'C' containing a cyano group \(\text{C≡N}\).
This sequence of reactions results in compound 'C'. The reaction likely leads to the formation of a cyano compound.
Checking the given options, the correct answer corresponds to the image identified by:
This option represents a benzene ring with a bromine, hydroxyl, and a cyno group as substituents, confirming it as product 'C'.
