\([(\dfrac{1}{3}+i\dfrac{7}{3})+(4+i\dfrac{1}{3})]-(-\dfrac{4}{3}+i)\)
\((\dfrac{1}{3}+4+\dfrac{4}{3}) +i(\dfrac{7}{3}+\dfrac{1}{3}-1) \)
\(=\dfrac{17}{3}+\dfrac{5}{3}i \) (Ans)