Given:
limx→π/2 tan 2x / (x − π/2)
Step 1: Substitute x = π/2 + h
As x → π/2, let
x = π/2 + h, where h → 0
Then,
2x = π + 2h
Step 2: Simplify the numerator
tan(2x) = tan(π + 2h)
Using identity,
tan(π + θ) = tan θ
tan(2x) = tan(2h)
Step 3: Rewrite the limit
limh→0 tan(2h) / h
= limh→0 2 · [tan(2h) / (2h)]
Step 4: Use standard limit
limθ→0 tan θ / θ = 1
So,
limh→0 tan(2h) / h = 2
Final Answer:
limx→π/2 tan(2x) / (x − π/2) = 2