Question

Evaluate the Given limit: \(\lim_{x\rightarrow 1}4\) \(\frac{4x-3}{x-2}\)

Answer 1

\(\lim_{x\rightarrow 1}4\) \(\frac{4x-3}{x-2}\) = 4(4) +\(\frac{3}{4-2}\) = 16 +\(\frac{3}{2}\) = \(\frac{19}{2}\)