Given:
limx→0 cos x / (π − x)
Step 1: Apply limits to numerator and denominator
As x → 0,
cos x → 1
π − x → π
Step 2: Evaluate the limit
limx→0 cos x / (π − x)
= 1 / π
Final Answer:
limx→0 cos x / (π − x) = 1 / π
The area of the region \( \{(x, y): 0 \leq y \leq x^2 + 1, \, 0 \leq y \leq x + 1, \, 0 \leq x \leq 2\ \) is:}