Given:
limx→0 (ax + x cos x) / (b sin x)
Step 1: Factor x from the numerator
= limx→0 x(a + cos x) / (b sin x)
Step 2: Rewrite the expression
= (1/b) · limx→0 (a + cos x) · (x / sin x)
Step 3: Apply standard limits
limx→0 (x / sin x) = 1
As x → 0,
cos x → 1
Step 4: Evaluate the limit
limx→0 (a + cos x) · (x / sin x)
= (a + 1) · 1
= a + 1
Therefore,
limx→0 (ax + x cos x) / (b sin x)
= (a + 1) / b
Final Answer:
limx→0 (ax + x cos x) / (b sin x) = (a + 1) / b
The area of the region \( \{(x, y): 0 \leq y \leq x^2 + 1, \, 0 \leq y \leq x + 1, \, 0 \leq x \leq 2\ \) is:}