Question:medium

Evaluate \(\lim_{x \to +\infty} \frac{x}{\sqrt{x^2 + 1000}}\)

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For limits at infinity of algebraic functions, you can ignore the lower-power constant terms.
\[ \lim_{x \to \infty} \frac{x}{\sqrt{x^2 + 1000}} \approx \lim_{x \to \infty} \frac{x}{\sqrt{x^2}} = \lim_{x \to \infty} \frac{x}{x} = 1 \]
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The Correct Option is B

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