Question:easy
Elimination after 4 half lives in first order kinetics is?
Elimination after 4 half lives in first order kinetics is?
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Remaining is (1/2) raised to the number of half lives.
Updated On: Jun 24, 2026
- 84%
- 93%
- 80.5%
- 4.75%
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The Correct Option is B
Solution and Explanation
Step 1: First order elimination means the remaining quantity is halved with every passing half life, a simple geometric decay.
Step 2: Compute the leftover fraction after $n=4$ half lives using $$\text{fraction remaining} = \left(\frac{1}{2}\right)^{4} = \frac{1}{16} = 6.25\%.$$
Step 3: The fraction cleared is the complement, $100\% - 6.25\% = 93.75\%$, matching the option closest to 93 percent.
\[\boxed{93\%}\]
Step 2: Compute the leftover fraction after $n=4$ half lives using $$\text{fraction remaining} = \left(\frac{1}{2}\right)^{4} = \frac{1}{16} = 6.25\%.$$
Step 3: The fraction cleared is the complement, $100\% - 6.25\% = 93.75\%$, matching the option closest to 93 percent.
\[\boxed{93\%}\]
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