Question:medium

Eight grams of Cu$^{66}$ undergoes radioactive decay and after 15 minutes only 1 g remains. The half-life, in minutes, is then}

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Use $\frac{N}{N_0}$ directly to avoid extra steps.
Updated On: May 1, 2026
  • $\frac{15\ln 2}{\ln 8}$
  • $\frac{15\ln 8}{\ln 2}$
  • $15/8$
  • $8/15$
  • $15\ln 2$
Show Solution

The Correct Option is A

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