During anaerobic glycolysis in muscle, each mole of glucose is converted into two moles of lactate, yielding two moles of ATP. Assume molar mass of glucose is \(180\ \text{g/mol}\). If \(1\ \text{kg}\) of glucose undergoes complete conversion to lactate, the number of moles of ATP produced is _ _ _. (round off to one decimal place)
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In anaerobic glycolysis, each glucose molecule produces only \(2\) ATP molecules because pyruvate is converted to lactate instead of entering oxidative phosphorylation.
Step 1: Set up the numbers.
We have $1$ kg, that is $1000$ g, of glucose, molar mass $180$ g/mol. Each mole of glucose yields $2$ ATP in anaerobic glycolysis.
Step 2: Find moles of glucose.
\[ n = \frac{1000}{180} = 5.555\ldots\ \text{mol} \]
Step 3: Find moles of ATP.
Multiply by $2$: \[ 5.555\ldots \times 2 = 11.111\ldots \]
Step 4: Round off.
To one decimal place this is $11.1$ mol ATP.