Question:medium

$\displaystyle \int \frac{x^4 - 1}{x + 1} \, dx$ is equal to:

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Always simplify rational functions using division before integrating.
Updated On: Apr 24, 2026
  • $\frac{x^4}{4} + \frac{x^3}{3} + \frac{x^2}{2} + x + C$
  • $\frac{x^4}{4} + \frac{x^3}{3} + \frac{x^2}{2} + 2x + C$
  • $\frac{x^4}{4} - \frac{x^3}{3} + \frac{x^2}{2} - x + C$
  • $\frac{x^4}{4} - \frac{x^3}{3} + \frac{x^2}{2} - 2x + C$
  • $-\frac{x^4}{4} - \frac{x^3}{3} - \frac{x^2}{2} - x + C$
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The Correct Option is C

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