Question:medium
$\displaystyle \int_{0}^{1} \left[\tan^{-1}\left(\frac{1}{1+x+x^2+x^3}\right) + \tan^{-1}(1+x+x^2+x^3)\right] dx$ is equal to:
$\displaystyle \int_{0}^{1} \left[\tan^{-1}\left(\frac{1}{1+x+x^2+x^3}\right) + \tan^{-1}(1+x+x^2+x^3)\right] dx$ is equal to:
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Look for inverse trig pair identities to simplify integrals instantly.
Updated On: Apr 24, 2026
- $\frac{\pi}{4}$
- $2\pi$
- $\frac{\pi}{2}$
- $1$
- $4\pi$
Show Solution
The Correct Option is C
Solution and Explanation
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