Displacement of a particle is given by \( x = t^{3/2} + 2 \). Find the time at which velocity becomes zero.
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Always double-check the given function. If the source intended a more typical exam problem like $x = t^2 - 2t + 2$, the derivative would be $v = 2t - 2$, yielding $t=1$ s when $v=0$.