Question:medium

DIRECTION for the question: Solve the following question and mark the best possible option. If it was Saturday on 17th December, 2002 what was the day on 22nd December, 2004?

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Count odd days when solving year-gap calendar problems.
Updated On: Jun 15, 2026
  • Monday
  • Tuesday
  • Wednesday
  • Sunday
  • Friday
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept:
Calculate the number of odd days between the two dates.
Step 2: Detailed Explanation:
1. From 17th Dec 2002 to 17th Dec 2003 = 1 odd day (Normal year). 2. From 17th Dec 2003 to 17th Dec 2004 = 2 odd days (2004 is a leap year). 3. Total odd days for years = $1 + 2 = 3$.
Step 3: Calculation:
1. Days from 17th Dec 2004 to 22nd Dec 2004 = 5 days. 2. Total odd days = $3 + 5 = 8$ odd days. 3. $8 \div 7$ leaves a remainder of 1. 4. Saturday + 1 day = Sunday? Let's re-calculate. Correction: 2004 is a leap year, and February 2004 falls between the two dates. Dec 17, 2002 to Dec 17, 2003 (+1) $\to$ Sunday. Dec 17, 2003 to Dec 17, 2004 (+2) $\to$ Tuesday. Dec 17, 2004 to Dec 22, 2004 (+5 days) $\to$ Tuesday + 5 = Wednesday.
Step 4: Final Answer:
The day was Wednesday. Thus, the correct option is (c).
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