Given that \(\triangle ABC \sim \triangle PQR\) using the SAS similarity criterion, it implies that two sides and the included angle of \(\triangle ABC\) are proportional and equal, respectively, to two sides and the included angle of \(\triangle PQR\). Devansh found that \(\angle C = \angle R\), establishing that the angles opposite the sides being compared are equal.
The SAS similarity criterion states:
Thus, in \(\triangle ABC \sim \triangle PQR\) by SAS similarity, we can deduce:
Based on this information, the ratio of corresponding sides should be equal:
This is because, with \(\angle C = \angle R\) being the included angle, the proportions of the sides \(\overline{AC}\) to \(\overline{BC}\) and \(\overline{PR}\) to \(\overline{QR}\) must remain consistent due to similarity.
Therefore, the option that was proved true is:
Let's rule out the other options:

let mid "“ point of sides of $\Delta$ are $(\frac{5}{2}, 3), (\frac{5}{2}, 7) \, \& \, (4, 5)$. If incentre is $(h, k)$ then value of $3h + k$ is:
