Step 1: Restate what SAS similarity needs.
For $\Delta ABC \sim \Delta PQR$ proved by SAS at the equal angle $\angle C = \angle R$, the two sides that form this angle in each triangle must be proportional, matched in the correct order.
Step 2: Identify the two sides at C and R.
At vertex $C$ the sides forming the angle are $AC$ and $BC$. At vertex $R$ the matching sides are $PR$ and $QR$. Since $C$ corresponds to $R$, $A$ corresponds to $P$ and $B$ corresponds to $Q$, so $AC$ must pair with $PR$, and $BC$ must pair with $QR$.
Step 3: Write the ratio and check it against the choices.
This pairing gives $\frac{AC}{PR} = \frac{BC}{QR}$, which rearranges to $\frac{AC}{BC} = \frac{PR}{QR}$. Checking the four options, only option (D) has exactly this form; the rest bring in $AB$ or $PQ$, sides that were never part of the SAS condition at $C$ and $R$.
\[ \boxed{\frac{AC}{BC} = \frac{PR}{QR}} \]