A lens's power \( P \) and focal length \( f \) are related by: \[ P = \frac{1}{f} \] where \( P \) is in diopters (D) and \( f \) is in meters.
If the power \( P = +2.0 \, {D} \), the focal length is: \[ f = \frac{1}{P} = \frac{1}{2.0} = 0.5 \, {m} \]
Therefore, the spectacles' lenses have a focal length of 0.5 meters.