Question:medium

Derivative of Average cost \((AC)=5+\frac{2}{Q}\) is:

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Convert fractions into powers before differentiating: \(\frac{1}{Q}=Q^{-1}\). Then use \(\frac{d}{dQ}(Q^n)=nQ^{n-1}\).
Updated On: May 22, 2026
  • \(-\frac{2}{Q^2}\)
  • \(\frac{2}{Q^2}\)
  • \(\frac{2}{Q}\)
  • \(\frac{1}{Q}\)
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The Correct Option is A

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