Question

Decreasing order of the hydrogen bonding in following forms of water is correctly represented by
A. Liquid water
B. Ice
C. Impure water 
Choose the correct answer from the options given below:

• A. $C >B >A$
• B. $B > A >C$
• C. $A=B >C$
• D. $A >B> C$

Answer 1

The Correct Option is B

To determine the correct order of hydrogen bonding strength among different forms of water, we need to consider their molecular structure and state. 

• Ice: In the solid state, water molecules form a crystalline structure with more extensive hydrogen bonding. Each water molecule can form up to four hydrogen bonds due to the tetrahedral arrangement in ice. This makes ice have the strongest hydrogen bonding among the three states listed.
• Liquid Water: In the liquid state, water molecules have more freedom to move compared to ice. Although hydrogen bonds are still present, they are less structured and constantly breaking and reforming. Thus, liquid water has weaker hydrogen bonding than ice.
• Impure Water: Impurities in water disrupt the hydrogen bonding between water molecules. As a result, impure water typically has the weakest hydrogen bonding of the three forms.

Based on the above reasoning, the decreasing order of hydrogen bonding strength is:

• Ice (B) > Liquid Water (A) > Impure Water (C)

Hence, the correct answer is:

$B > A >C$