Question

David invested in three schemes A, B, C at $10\%$, $12\%$, $15\%$ p.a. respectively. The total interest in one year was ₹3200. Also, $C$ was $150\%$ of $A$ and $240\%$ of $B$. What was the amount invested in $B$? 

• A. ₹5000
• B. ₹6500
• C. ₹8000
• D. cannot be determined

Hint:

Translate percentage relations into multipliers (e.g., $150\%\!=1.5$). Reduce to one variable, then use the interest equation.

Answer 1

The Correct Option is A

Step 1: Given \(C=2.4B\) and \(C=1.5A\), so \(A=\dfrac{2.4B}{1.5}=1.6B\).

Step 2: Total interest: \[ 0.10(1.6B)+0.12B+0.15(2.4B)=0.64B=3200 \]

Step 3: Solve: \[ B=\frac{3200}{0.64}=\boxed{₹5000} \]