Question:medium

Cyclohexene on oxidation by \(\text{KMnO}_4\) in dilute \(\text{H}_2\text{SO}_4\) produces

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Acidified KMnO4 cleaves the C=C bond; in a ring this opens the ring to a dicarboxylic acid.
Updated On: Oct 1, 2026
  • benzene-1,4-dicarboxylic acid
  • pent-2-enoic acid
  • hexane-1,6-dioic acid
  • benzene-1,2-dicarboxylic acid
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The Correct Option is C

Solution and Explanation

Step 1: Follow the carbon count:
Oxidative cleavage does not remove carbons from the ring. Cyclohexene has 6 carbons, so the product must have 6 carbons in one chain.

Step 2: Track the double bond:
Cutting the ring at the C=C opens it into a chain with two new ends. Each end carbon had one H and gets oxidised to $\text{COOH}$.

Step 3: Write the structure:
\[ \text{HOOC-CH}_2\text{CH}_2\text{CH}_2\text{CH}_2\text{-COOH} \]
This is hexanedioic acid, option C.

Final Answer:
Ring-opening oxidation gives adipic acid, hexane-1,6-dioic acid. \[ \boxed{\text{(C) }\text{hexane-1,6-dioic acid}} \]
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