Crude oil of kinematic viscosity 2.25 Stokes flows through a 20 cm diameter pipe. If the rate of flow is 1.5 liters/sec, what will be the type of flow?

Question

A soap bubble of radius \(r = 1\,\text{mm}\) is rising in a liquid of density \( \rho = 2000\,\text{kg/m}^3 \). At the instant the bubble is rising upward with constant velocity \(v = \tfrac{1}{2}\,\text{cm/s}\). Find the coefficient of viscosity \( (\eta) \).

Answer 1

Flow type is ascertained by the Reynolds number formula:

\( Re = \frac{\rho v D}{\mu} \)

With \( D = 20 \, \text{cm}, \, v = 1.5 \, \text{L/sec}, \) and kinematic viscosity \( u = 2.25 \, \text{Stokes}, \) the computed Reynolds number is under 2000, indicating laminar flow.

Crude oil of kinematic viscosity 2.25 Stokes flows through a 20 cm diameter pipe. If the rate of flow is 1.5 liters/sec, what will be the type of flow?

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The Correct Option is A

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