Question:medium

Convert the following temperatures to the Celsius scale.
(a) 293 K
(b) 470 K

Updated On: Jan 19, 2026
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Solution and Explanation

Step 1: Conversion Formula

The formula for converting from Kelvin (\( T_K \)) to Celsius (\( T_C \)) is: \[ T_C = T_K - 273.15 \]

(a) Convert \( 293 \, \text{K} \) to Celsius:

Using the formula: \[ T_C = 293 - 273.15 = 19.85^\circ C \] So, \( 293 \, \text{K} \) is approximately \( 19.85^\circ C \).

(b) Convert \( 470 \, \text{K} \) to Celsius:

Using the formula: \[ T_C = 470 - 273.15 = 196.85^\circ C \] So, \( 470 \, \text{K} \) is approximately \( 196.85^\circ C \).

Conclusion:

The temperatures in Celsius are:

  • \( 293 \, \text{K} = 19.85^\circ C \)
  • \( 470 \, \text{K} = 196.85^\circ C \)
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(Street Plan) : A city has two main roads which cross each other at the centre of the city. These two roads are along the North-South direction and East-West direction.

All the other streets of the city run parallel to these roads and are 200 m apart. There are 5 streets in each direction. Using 1cm = 200 m, draw a model of the city on your notebook. Represent the roads/streets by single lines. There are many cross- streets in your model. A particular cross-street is made by two streets, one running in the North - South direction and another in the East - West direction. Each cross street is referred to in the following manner : If the 2nd street running in the North - South direction and 5th in the East - West direction meet at some crossing, then we will call this cross-street (2, 5). Using this convention, find: 

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(ii) how many cross - streets can be referred to as (3, 4).

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