Question:medium

Considering earth to be a sphere of radius $R$ having uniform density $\rho$, then value of acceleration due to gravity $g$ in terms of $R,\rho$ and $G$ is

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Physics Tip : For same density bodies, surface gravity is proportional to radius.
Updated On: Apr 23, 2026
  • $g=\sqrt{\dfrac{3\pi R}{\rho G}}$
  • $g=\sqrt{\dfrac{4}{3}\pi \rho G R}$
  • $g=\dfrac{4}{3}\pi \rho G R$
  • $g=\dfrac{GM}{\rho R^2}$
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The Correct Option is C

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