Question:hard

Consider three identical non-interacting first order processes in series, each having unit gain and a time constant of 2 min. Tuning of a proportional controller using the closed loop Ziegler-Nichols technique is considered. Which one of the following is the ultimate period of sustained cycling (in min per cycle)?

Show Hint

At the ultimate frequency the total phase lag of the three lags equals \(-180^\circ\); each lag contributes \(-60^\circ\), giving \(\omega_u\tau = \tan 60^\circ = \sqrt{3}\).
Updated On: Aug 10, 2026
  • \(4\sqrt{3}\,\pi\)
  • \(\dfrac{\sqrt{3}\,\pi}{4}\)
  • \(\dfrac{4\pi}{\sqrt{3}}\)
  • \(\dfrac{\pi}{4\sqrt{3}}\)
Show Solution

The Correct Option is C

Solution and Explanation

Using the Routh array on the expanded characteristic polynomial $(1+\tau s)^3+K_c=0$, the s^1 row vanishing gives $K_{cu}=8$, and the auxiliary equation $3\tau^2s^2+9=0$ gives $\omega_u=\sqrt3/\tau$. With $\tau=2$ min, $P_u=4\pi/\sqrt3$ min/cycle, matching option (C).

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