Consider the probability density function
$ f(x;\theta) = \begin{cases} \frac{2x}{5\theta} & ; 0 \le x \le \theta \ \frac{2(5-x)}{5(5-\theta)} & ; \theta \le x \le 5 \end{cases} $
For a sample of size 3, let the observations are, $ x_1 = 1, x_2 = 4, x_3 = 2 $. Then, the value of likelihood function at $ \theta=2 $ is

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$ \frac{4}{375} $

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The Correct Option is D

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