Question:medium

Consider the lines \[ L_1: 2x+3y+1=0 \] and \[ L_2: 3x-2y+1=0. \] The locus of a variable point that is equidistant from the two lines \(L_1=0\) and \(L_2=0\) is

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The locus of points equidistant from two intersecting lines is the pair of angle bisectors. Using the distance formula and squaring both sides directly gives the combined equation of the two bisectors.
Updated On: Jul 29, 2026
  • \[ 5x^2-24xy-5y^2+2x-10y=0 \]
  • \[ x-5y=0 \]
  • \[ 5x+y=0 \]
  • \[ 5x^2-24xy-5y^2=0 \]
Show Solution

The Correct Option is A

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