Step 1: Determine Rank.
The matrix $A$ has dimensions $2 \times 3$. The two row vectors $[1, 1, 1]$ and $[1, 0, 2]$ are linearly independent because one is not a scalar multiple of the other. Thus, $\text{Rank}(A) = 2$.
Step 2: Apply Rank-Nullity Theorem.
$\text{Dimension of Null Space} = n - \text{Rank}(A) = 3 - 2 = 1$. The solution to a homogeneous system $Ax = 0$ is the Null Space.
Step 3: Geometric Interpretation.
A 1-dimensional subspace in $\mathbb{R}^3$ corresponds to a straight line passing through the origin.