Step 1: Evaluate the parts:
p: implication with true hypothesis and false conclusion, false. q: "roots real" is false, "Mumbai in Maharashtra" is true, and the biconditional of false and true is false. r: $p \lor \sim q$, with $\sim q = T$, is true.
Step 2: Table of values:
p = F, q = F, r = T.
Step 3: Check each option quickly:
Any option that needs p or q to be true on its own, or both p and q, fails except where r alone can carry the disjunction. Only $(p \land q) \lor r$ has r as a free disjunct, so it is $F \lor T = T$. The others reduce to F.
Final Answer:
Option (D) has truth value T.
\[ \boxed{(p\wedge q)\vee r} \]