To determine the correct answer, let's analyze each of the given statements:
- (A) Propanal and Propanone are functional isomers.
- Propanal (CH3CH2CHO) and Propanone (CH3COCH3) have the same molecular formula (C3H6O) but differ in the functional groups. Propanal is an aldehyde and Propanone is a ketone.
- Thus, they are functional isomers.
- (B) Ethoxyethane and methoxypropane are metameres.
- Ethoxyethane (C2H5-O-C2H5) and methoxypropane (CH3-O-CH2CH2CH3) have the same molecular formula (C4H10O) and belong to the same homologous series (ethers), but differ in the alkyl groups attached to the oxygen atom.
- This type of isomerism is called metamerism.
- (C) But-2-ene shows optical isomerism.
- Optical isomerism typically occurs in chiral molecules that have an asymmetrical carbon atom.
- But-2-ene is symmetrical and does not have chiral centers, thus it does not exhibit optical isomerism. It can, however, exhibit geometrical (cis-trans) isomerism.
- (D) But-1-ene and But-2-ene are functional isomers.
- But-1-ene and But-2-ene are both alkenes with the same molecular formula (C4H8) but differ in the position of the double bond.
- This is an example of position isomerism, not functional isomerism.
- (E) Pentane and 2,2-dimethylpropane are chain isomers.
- Pentane (CH3(CH2)3CH3) and 2,2-dimethylpropane (C(CH3)4) have the same molecular formula (C5H12), but differ in the carbon chain arrangement.
- This is an example of chain isomerism.
Based on this analysis, the correct statements are (A), (B), and (E). Therefore, the correct answer is: A, B, E only.