Step 1: Reflexive Property.
A relation \( R \) is reflexive if for every element \( a \in I \), the pair \( (a,a) \) is in \( R \). Since \( R \) does not contain \( (4,4), (5,5), (6,6), (7,7) \), it is not reflexive.
Step 2: Symmetric Property.
A relation is symmetric if \( (a,b) \in R \) implies \( (b,a) \in R \). The presence of pairs like \( (4,5) \) and \( (5,4) \) (and others) confirms that \( R \) is symmetric.
Step 3: Transitive Property.
A relation is transitive if \( (a,b) \in R \) and \( (b,c) \in R \) implies \( (a,c) \in R \). However, \( (4,5) \in R \) and \( (5,4) \in R \) would require \( (4,4) \in R \) for transitivity. As \( (4,4) \) is not in \( R \), the relation is not transitive.
Step 4: Antisymmetric Property.
A relation is antisymmetric if \( (a,b) \in R \) and \( (b,a) \in R \) implies \( a = b \). For example, \( (4,5) \in R \) and \( (5,4) \in R \), but \( 4 eq 5 \). Therefore, \( R \) is not antisymmetric.
Step 5: Conclusion.
As the relation lacks the transitive property, the conclusion is that options A, C, and D are correct.
The speed-density relation on a one-way, single lane road is shown in the figure, where speed \( u \) is in km/hour and density \( k \) is in vehicles/km. The maximum flow (in vehicles/hour) on this road is

Let \( A = \{-3, -2, -1, 0, 1, 2, 3\} \). A relation \( R \) is defined such that \( xRy \) if \( y = \max(x, 1) \). The number of elements required to make it reflexive is \( l \), the number of elements required to make it symmetric is \( m \), and the number of elements in the relation \( R \) is \( n \). Then the value of \( l + m + n \) is equal to: