Question:medium

Consider the following reaction sequence:

Given: Compound (x) has percentage composition $76.6%\ \text{C}$, $6.38%\ \text{H}$ and vapour density $=47$. Compound (y) develops a characteristic colour with neutral $\mathrm{FeCl_3}$ solution. Identify the {INCORRECT statement.}

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Carboxylic acids are always stronger acids than phenols, and the Kolbe–Schmitt reaction is a key test reaction for phenol.

Updated On: Mar 25, 2026

Compound $y$ will dissolve in $\mathrm{NaHCO_3}$ and evolve a gas.
Both compounds $x$ and $y$ will burn with sooty flame.
Compound $x$ is more acidic than compound $y$.
Both compounds $x$ and $y$ will dissolve in $\mathrm{NaOH}$.

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The Correct Option is C

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Questions Asked in JEE Main exam

If $Z$ be a complex number such that $|Z + 2| = |Z - 2|$ and $\text{arg} \left( \frac{Z - 3}{Z + 1} \right) = \frac{\pi}{4}$, then the value of $|Z|^2$ is

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Complex numbers

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Let the lines $L_1 : \vec r = \hat i + 2\hat j + 3\hat k + \lambda(2\hat i + 3\hat j + 4\hat k)$, $\lambda \in \mathbb{R}$ and $L_2 : \vec r = (4\hat i + \hat j) + \mu(5\hat i + + 2\hat j + \hat k)$, $\mu \in \mathbb{R}$ intersect at the point $R$. Let $P$ and $Q$ be the points lying on lines $L_1$ and $L_2$, respectively, such that $|PR|=\sqrt{29}$ and $|PQ|=\sqrt{\frac{47}{3}}$. If the point $P$ lies in the first octant, then $27(QR)^2$ is equal to}