




The given reaction involves the cleavage of an ether linkage in the presence of hydrogen iodide (HI) under heat (represented by Δ). This is a typical reaction where ethers are cleaved to give alcohols and alkyl halides.
The reaction is:
In this reaction, the ether linkage is between the benzyl group and the phenyl group, represented as Ar–O–Ar' (where Ar represents an aromatic ring).
When HI reacts with this ether, the products formed are an alkyl halide and an alcohol. In this case, benzyl iodide and phenol are formed. Here is how the reaction proceeds:
The final products are benzyl iodide (PhCH2I) and phenol (PhOH).
This corresponds to the correct answer:
Therefore, the correct answer is that Product A is Benzyl Iodide and Product B is Phenol.