Consider the following logic circuit. The circuit consists of three gates: an AND gate, an OR gate, and a NOT gate. The inputs to the AND gate are \( A = 1 \) and \( B = 0 \). The output of the AND gate is fed into the input of the OR gate, which has another input \( C = 1 \). The output of the OR gate is then passed through a NOT gate. What is the final output of the circuit?
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In logic gate problems, break down the circuit step by step, evaluating the output of each gate one at a time. Remember, AND = 1 only when both inputs are 1, OR = 1 if at least one input is 1, and NOT inverts the input.
The circuit's output is determined through a sequential evaluation:- The AND gate receives inputs \( A = 1 \) and \( B = 0 \). Its output is calculated as: \[ A \cdot B = 1 \cdot 0 = 0. \]- The AND gate's output (0) is then directed to the OR gate. This OR gate processes inputs of 0 (from the AND gate) and \( C = 1 \). Its output is: \[ 0 + 1 = 1. \]- Subsequently, the OR gate's output (1) is passed to a NOT gate. The NOT gate inverts its input, resulting in the final output: \[ \text{NOT}(1) = 0. \]Therefore, the circuit's ultimate output is 0.