Consider the following C code segment:
a = b + c;
e = a + 1;
d = b + c;
f = d + 1;
g = e + f; In a compiler, this code is represented internally as a Directed Acyclic Graph (DAG). The number of nodes in the DAG is \(\underline{\hspace{2cm}}\).
Step 1: Identify common subexpressions.
In the given expression, the subexpression \( b + c \) occurs more than once.
When constructing a DAG (Directed Acyclic Graph), such common subexpressions are represented by a single node to avoid redundant computation.
Step 2: Identify distinct operation nodes.
After eliminating redundancy, the distinct arithmetic operations that must be represented are:
\[
b + c,\quad a + 1,\quad d + 1,\quad e + f
\]
Each of these corresponds to one internal (operator) node in the DAG.
Step 3: Identify operand (leaf) nodes.
The operands that appear in the expression and are required as leaves in the DAG are:
\[
b,\ c,\ 1
\]
(Note that constants such as \(1\) are represented only once, even if reused.)
Step 4: Count total DAG nodes.
- Operand (leaf) nodes: \( b, c, 1 \) → 3 nodes
- Operator (internal) nodes: \( b+c,\ a+1,\ d+1,\ e+f \) → 3 nodes
Therefore, the total number of nodes in the DAG is: \[ 3 + 3 = 6 \]
Final Answer:
\[
\boxed{6}
\]
Consider the following ANSI C code segment:
z = x + 3 + y->f1 + y->f2;
for (i = 0; i < 200; i = i + 2){
if (z > i) {
p = p + x + 3;
q = q + y->f1;
} else {
p = p + y->f2;
q = q + x + 3;
}
} Assume that the variable \(y\) points to a struct (allocated on the heap) containing two fields \(f1\) and \(f2\), and the local variables \(x, y, z, p, q,\) and \(i\) are allotted registers. Common sub-expression elimination (CSE) optimization is applied on the code. The number of addition and dereference operations (of the form \(y \rightarrow f1\) or \(y \rightarrow f2\)) in the optimized code, respectively, are: