Question

Consider the following \[ \begin{aligned} \text{I.} \quad & \text{1-Bromo-1-phenylpropane} \\ \text{II.} \quad & \text{1-Bromo-3-}\mathit{n}\text{-butyl-2-methylbenzene} \end{aligned} \] Bromides I and II are classified respectively as

• A. Benzyl ; Aryl
• B. Aryl ; Aryl
• C. Primary ; Benzyl
• D. Aryl ; Primary \bigskip

Hint:

\textbf{Benzylic halide:} Halogen attached to the carbon adjacent to a benzene ring. \textbf{Aryl halide:} Halogen directly attached to the benzene ring.

Answer 1

The Correct Option is A

Step 1: I: 1-bromo-1-phenylpropane → Br on benzylic carbon → benzyl bromide. II: 1-bromo-3-n-butyl-2-methylbenzene → Br on ring → aryl halide.

Step 2: Write the final answer. \(\boxed{\text{I -- Benzyl,\qquad II -- Aryl}}\)