Question

Consider the following alphabet series: A B C D E F G H I J K L M N O P Q R S T U V W X Y Z If the second half of the given alphabet series is written in reverse order, which letter will be seventh to the right of the twelfth letter from the left end?

• A. R
• B. S
• C. U
• D. T

Hint:

When dealing with alphabet series, reversing half of the sequence and counting positions can help identify the correct answer.

Answer 1

The Correct Option is C

Step 1: Reverse the second half of the alphabet.
The second half of the alphabet is: \[M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z\] Reversing this yields: \[Z, Y, X, W, V, U, T, S, R, Q, P, O, N, M\]

Step 2: Construct the new series.
The modified series is: \[A, B, C, D, E, F, G, H, I, J, K, L, Z, Y, X, W, V, U, T, S, R, Q, P, O, N, M\]

Step 3: Identify the twelfth letter and the seventh letter to its right.
The twelfth letter is \( L \). Counting seven letters to the right of \( L \) results in: \[Z, Y, X, W, V, U, T\]The seventh letter to the right of \( L \) is \( U \). Therefore, the answer is 3. U.