Question

Consider the elements with atomic numbers Z = 8, 9, 11, 19 and 20. The number of ionic compounds possible with the elements having these atomic numbers is

• A. 6
• B. 5
• C. 10
• D. 8

Hint:

To solve this quickly, just classify the elements into metals and non-metals. The total number of binary ionic compounds will be (number of metals) \(\times\) (number of non-metals).

Answer 1

The Correct Option is A

Step 1: Understanding the Question:
Elements Z=8,9,11,19,20. How many binary ionic compounds possible?

Step 2: Key Concept (Alternate):
Metals (Na,K,Ca) + Non-metals (O,F). Each metal pairs with each non-metal.

Step 3: Detailed Explanation:
Metals: 3 (Z=11,19,20). Non-metals: 2 (Z=8,9). Total combinations = 3×2 = 6.

Step 4: Final Answer:
6 ionic compounds possible.