Step 1 (Alternate method - complement counting): The total number of subsets of {A, B, C, D} is 2^4 = 16 (including the empty set). Count the subsets that fail to be superkeys instead, then subtract from 16.
Step 2: A subset S is NOT a superkey exactly when it contains neither {A, B} nor {A, C} as a subset, i.e. S is missing at least one of A or B, AND S is missing at least one of A or C.
Step 3 (Case i - S does not contain A at all): Then S automatically cannot contain {A, B} or {A, C} (both require A). With A excluded and B, C, D free, this gives 2^3 = 8 such subsets.
Step 4 (Case ii - S contains A but is still not a superkey): Then S must exclude B (otherwise {A, B} would be contained) AND exclude C (otherwise {A, C} would be contained). With A included, B and C excluded, and D free, this gives 2^1 = 2 such subsets: {A} and {A, D}.
Step 5 (Total non-superkeys): 8 + 2 = 10.
Step 6 (Superkeys): Total subsets - non-superkeys = 16 - 10 = 6, matching the direct union calculation.
\[ \boxed{6} \]