Question

Consider a parallel plate capacitor of area \(A\) of each plate and separation \(d\) between the plates. If \(E\) is the electric field and \(\varepsilon_0\) is the permittivity of free space between the plates, then potential energy stored in the capacitor is:

• A. \(\displaystyle \frac{1}{2}\varepsilon_0 E^2Ad\)
• B. \(\displaystyle \frac{3}{4}\varepsilon_0 E^2Ad\)
• C. \(\displaystyle \frac{1}{4}\varepsilon_0 E^2Ad\)
• D. \(\displaystyle \varepsilon_0 E^2Ad\)

Hint:

Energy density in an electric field is \(\frac{1}{2}\varepsilon_0E^2\). Multiply it by volume \(Ad\) to get total energy stored.

Answer 1

The Correct Option is A