Question:medium

Consider a block of mass \(m\) hanging using a string and pulley arrangement, as shown in the figure. The weight \(mg\) and tension \(T\) are working on the block in such a way that the block is not moving and the string is parallel to the perfectly vertical wall. If the block is just in contact but not attached/fixed with the wall and the coefficient of static friction is \(\mu\), then the static frictional force acting on the block is

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Friction depends on normal reaction. If the normal reaction is zero, then frictional force is also zero, even if the surfaces are in contact.
Updated On: Jun 5, 2026
  • \(0\)
  • \(\mu mg\)
  • \(\mu T\)
  • \(\mu \left(\dfrac{mg+T}{2}\right)\)
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: List the forces on the block.
The block feels its weight $mg$ pulling straight down and the string tension $T$ pulling straight up. The string runs parallel to the vertical wall.

Step 2: Look for any sideways push.
Because the string is vertical, the tension has no horizontal part. Nothing pushes the block sideways into the wall.

Step 3: Find the normal force.
With no horizontal push, the wall presses back with zero force, so the normal reaction is $N = 0$.

Step 4: Apply the friction limit.
Static friction can never beat $\mu N$. With $N=0$, the most friction available is $\mu \times 0 = 0$, and since nothing is trying to slide the block anyway, the actual friction is also zero.

Step 5: Answer.
\[ \boxed{0} \]
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