To address this problem, we must examine the relationship between mole fractions in the liquid and vapor phases for a binary ideal solution containing volatile components 1 and 2. This relationship is established using Raoult's Law and Dalton's Law for ideal solutions and vapors.
- Let \(x_1\) represent the mole fraction of component 1 in the liquid phase and \(y_1\) represent it in the vapor phase.
- Raoult's Law states that the partial pressure of component 1, denoted as \(p_1\), is calculated as:
\[p_1 = x_1 \cdot p_1^0\]- Here, \(p_1^0\) signifies the vapor pressure of pure component 1.
- The same principle applies to component 2:
\[p_2 = x_2 \cdot p_2^0\]- where \(p_2^0\) is the vapor pressure of pure component 2.
- Dalton's Law for total pressure is expressed as:
\[P_{\text{total}} = p_1 + p_2\]- The mole fraction in the vapor phase, \(y_1\), can be expressed as:
\[y_1 = \frac{p_1}{P_{\text{total}}} = \frac{x_1 \cdot p_1^0}{x_1 \cdot p_1^0 + x_2 \cdot p_2^0}\]- The current question involves a linear plot of \(\frac{1}{x_1}\) against \(\frac{1}{y_1}\). By rearranging the terms from step 5, we obtain:
\[\frac{y_1}{x_1} = \frac{p_1^0}{p_1^0 + \frac{x_2}{x_1} \cdot p_2^0}\]- Inverting this equation to align with the linear form presented in the question yields:
\[\frac{1}{y_1} = \frac{1}{x_1} \cdot \frac{p_1^0 + x_2/x_1 \cdot p_2^0}{p_1^0}\]- The slope of this line is determined to be:
\[\frac{p_2^0}{p_1^0}\]- Considering the entire equation setup, the intercept of the line is:
\[1 - \frac{p_1^0}{p_2^0}\]Consequently, the correct answer corresponds to the option presenting a slope of \(\frac{p_1^0}{p_2^0}\) and an intercept of \(1 - \frac{p_1^0}{p_2^0}\), aligning with the question's interpretation.